Austin triangle
AssigneeKenneth H Austin
InventorKenneth H Austin
Life of this patent
Estimating the term…
Abstract
I have discovered it is possible to find an indirect measurement if the vertex angle is given and the sides and the diameter are given. Using an instrument having the shape of an isosceles triangle it is possible to have a vertex angle and two congruent sides that correspond to the diameter of a circle or the side of a cube to find an indirect measurement to solve four classic problems, one is squaring the area of a circle, two is squaring the area of a sphere, three is finding the cube root of a sphere and cubing the volume, four is to double the volume of a cube.
Claims4
An apparatus for converting measurements of circular areas to corresponding square areas, comprising an isosceles triangle having a vertex angle of 52.589 degrees, wherein the adjacent and opposite sides of the isosceles triangle are always congruent and the hypotenuse will always equal the square root of the area of a circle with a diameter congruent to the adjacent and/or opposite side of the vertex angle of the isosceles triangle.
An apparatus for converting measurements of spherical volumes to corresponding cuboidal volumes, comprising an isosceles triangle having a vertex angle of 47 degrees, wherein the adjacent and opposite sides of an isosceles triangle are always congruent and the hypotenuse will always equal the cube root of a sphere with a diameter congruent to the adjacent and/or opposite sides.
An apparatus for doubling the volume of a cuboidal structure, comprising an isosceles triangle having a vertex angle of 78.09 degrees, wherein the adjacent and/or opposite sides are always congruent and the hypotenuse will always equal the cube root of a cube doubled in volume to a cube that has sides congruent to the adjacent and/or opposite sides of an isosceles triangle.
Dependencies are inferred from the claim text.