Olefin-based polymer
AssigneeLG Chem, Ltd.
InventorsIn Sung Park, Eun Jung Lee, Hyun Jin Ju, Sang Eun Park, Kyung Bok Bae, Choong Hoon Lee
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Abstract
The present invention relates to an olefin-based polymer, which has (1) a density (d) ranging from 0.850 g/cc to 0.865 g/cc, (2) a melt index (MI, 190° C., 2.16 kg load conditions) ranging from 0.1 g/10 min to 3.0 g/10 min, (3) a melt temperature (Tm) of 10° C. to 100° C., and (4) a hardness (H, Shore A), the density (d) and the melt temperature (Tm) satisfying Equation 1, and Equation 2 or 3. The olefin-based polymer according to the present invention has low hardness and improved foaming properties, and exhibits improved impact strength at compounding.
Claims15
An olefin-based polymer, which has (1) a density (d) ranging from 0.850 g/cc to 0.865 g/cc, (2) a melt index (MI, 190° C., 2.16 kg load conditions) ranging from 0.1 g/10 min to 3.0 g/10 min, (3) a melt temperature (Tm) of 10° C. to 100° C., and (4) a hardness (H, Shore A) defined by the following Equation 1:
- H=1293×d+A, [Equation 1]
- in Equation 1, A satisfies Equation 2 or Equation 3 below:
- Tm×(0.855×Tm−62)<A<d×−1238, [Equation 2]
- d×−1238<A<Tm×(0.855×Tm−62), [Equation 3]
- in Equations 1 to 3, H is the hardness (shore A), d is the density, and Tm is the melt temperature.
An olefin-based polymer, which has:
- a density (d) ranging from 0.850 g/cc to 0.865 g/cc;
- a melt index (MI, 190° C., 2.16 kg load conditions) ranging from 0.1 g/10 min to 3.0 g/10 min;
- a soluble fraction (SF) of 10 wt % or more at −20° C. in cross-fractionation chromatography (CFC), in which a weight average molecular weight (Mw) of the soluble fraction is in a range of 50,000 g/mol to 120,000 g/mol;
- a vinyl group content per 1,000 carbon atoms of 0.06 to 1, which is determined by infrared absorption measurement;
- a MFR10/MFR2.16 of 8.5 or less, which is a ratio of a melt flow rate measured ASTM D1238 at 190° C. 10 kg load and ASTM D1238 at 190° C. 2.16 kg load;
- and
- a hardness (H, Shore A) defined by the following Equation 1:
- H=1293×d+A, [Equation 1]
- in Equation 1, A satisfies Equation 2 or Equation 3 below:
- Tm×(0.855×Tm−62)<A<d×−1238, [Equation 2]
- d×−1238<A<Tm×(0.855×Tm−62), [Equation 3]
- in Equations 1 to 3, H is the hardness (shore A), d is the density, and Tm is the melt temperature.
Dependencies are inferred from the claim text.